Pakistan cricket team's amazing work continues on the Zimbabwe tour. After winning the ODI series, it easily defeated host Zimbabwe in the first T20 match. Now in the second T20, Zimbabwe's batsmen surrendered in front of Pakistani bowling in such a way that after a strong start, suddenly the entire team was out within 20 runs. The balls of Pakistan's young spinner Sufiyan Muqeem wreaked such havoc that the entire team collapsed for just 57 runs. In this way, it also proved to be Zimbabwe's smallest score in T20 International.

In this second match of the series played on Tuesday 3 December in Bulawayo, host Zimbabwe batted first. Despite the defeat of the first match, Sikandar Raza did not make any changes in his playing eleven. At the same time, Pakistan also continued to rely only on match-winning players. Pakistan's trust proved correct but Zimbabwe was again disappointed and this time it had to face more embarrassment than disappointment.

Zimbabwe made an explosive start to their innings. For that, the opening pair of Brian Bennett and Tadivanashe Marumani attacked the Pakistani bowlers as soon as they arrived. Both of them had scored 37 runs in just 4 overs. Till now everything was fine but the sequence of wickets which started from the 5th over, stopped with the team being all out. Zimbabwe lost the first wicket on the score of 37 and then the team collapsed on 57 runs. That means Zimbabwe lost all 10 wickets in just 20 runs.

The reason for this condition of Zimbabwe was 25 year old left arm spinner Sufiyan Mukeem. Mukim, playing only his 7th T20 match, destroyed half of the Zimbabwe team within 3 overs. Even before Mukeem came to bowl, Zimbabwe had lost 4 wickets for 44 runs. Then after Mukim's entry the entire innings collapsed. This spinner took 5 wickets of Zimbabwe in just 2.4 overs i.e. 16 balls. Not only this, he spent only 3 runs during this period. In this way, Muqim also made the record of best bowling figure for Pakistan in T20 International.

(News is being updated)