Rohit Sharma won the toss and chose to bat, Kuldeep Yadav entered the playing XI, this flop player was out
Team India is going to start its Super-8 in the ICC T20 World Cup 2024. It is going to face Afghanistan (IND vs AFG) team in Barbados. The first ball of the match will be bowled on June 20 at 8 pm as per Indian time. After a great performance in the group stage, Rohit Sharma and company would like to start the Super-8 with a bang.
On the other hand, the Afghan team will also be eyeing its first win. At the same time, before the IND vs AFG match started, the captains were called on the field. After this, the coin was tossed, in which Rohit Sharma won and he decided to bowl first.
IND vs AFG: India chose to bowl after winning the toss
- On Thursday, the Indian team is going to play its first match of the Super-8 of the T20 World Cup 2024 against Afghanistan.
On June 20, both the teams will face each other at Kensington Oval ground in Barbados.
- This match is very special for both the teams in terms of getting a ticket to the semi-finals. India reached the Super-8 by winning three matches in the league stage.
- At the same time, the Afghan team also looked amazing in the group stage. In such a situation, a tough competition can be seen between the two teams in the IND vs AFG match.
This strong player entered the team
- However, before the start of the IND vs AFG match, the toss was done, which fell in favor of Team India.
After this, captain Rohit Sharma decided to bowl first.
IND vs AFG: India-Afghanistan playing XI
- Team India Playing XI: Rohit Sharma (captain), Virat Kohli, Rishabh Pant (wicketkeeper), Suryakumar Yadav, Shivam Dubey, Hardik Pandya, Ravindra Jadeja, Axar Patel, Kuldeep Yadav, Jasprit Bumrah, Arshdeep Singh.
- Afghanistan's playing XI: Rahmanullah Gurbaz (wicketkeeper), Ibrahim Zadran, Gulbadin Naib, Azmatullah Omarzai, Najibullah Zadran, Mohammad Nabi, Karim Janat, Rashid Khan (captain), Noor Ahmed, Naveen Ul Haq, Fazalhaq Farooqi.